What are the solutions to the equation 7x^2-7x+9=0 ?

The solutions to the equation 7x^2-7x+9=0 are x= 1/2+i(sqrt(203))/(14),x= 1/2-i(sqrt(203))/(14)

Find the zeros of 7x^2-7x+9=0

The zeros of 7x^2-7x+9=0 are x= 1/2+i(sqrt(203))/(14),x= 1/2-i(sqrt(203))/(14)

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7 x^{2} - 7 x + 9 = 0

x = \frac{1}{2} + i \frac{203}{14}, x = \frac{1}{2} - i \frac{203}{14}

Solution steps

7 x^{2} - 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 7 \cdot 9}{2 \cdot 7}

Simplify

(- 7)^{2} - 4 \cdot 7 \cdot 9 : 203 i

x_{1, 2} = \frac{- ( - 7 ) \pm 203 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 203 i}{2 \cdot 7}, x_{2} = \frac{- ( - 7 ) - 203 i}{2 \cdot 7}

x = \frac{- ( - 7 ) + 203 i}{2 \cdot 7} : \frac{1}{2} + i \frac{203}{14}

x = \frac{- ( - 7 ) - 203 i}{2 \cdot 7} : \frac{1}{2} - i \frac{203}{14}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{203}{14}, x = \frac{1}{2} - i \frac{203}{14}

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What are the solutions to the equation 7x^2-7x+9=0 ?
The solutions to the equation 7x^2-7x+9=0 are x= 1/2+i(sqrt(203))/(14),x= 1/2-i(sqrt(203))/(14)
Find the zeros of 7x^2-7x+9=0
The zeros of 7x^2-7x+9=0 are x= 1/2+i(sqrt(203))/(14),x= 1/2-i(sqrt(203))/(14)