What is the answer to sqrt(2^{3x+5)}=9^{x+1} ?

The answer to sqrt(2^{3x+5)}=9^{x+1} is x=(4ln(3)-5ln(2))/(3ln(2)-4ln(3))

Solve for x: sqrt(2^{3x+5)}=9^{x+1}

The solution is x=(4ln(3)-5ln(2))/(3ln(2)-4ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{3 x + 5} = 9^{x + 1}

x = \frac{4 ln ( 3 ) - 5 ln ( 2 )}{3 ln ( 2 ) - 4 ln ( 3 )}

Decimal Notation

x = - 0.40117 \dots

Solution steps

2^{3 x + 5} = 9^{x + 1}

Apply exponent rules

(3 x + 5) \frac{1}{2} ln (2) = (x + 1) ln (9)

Solve

(3 x + 5) \frac{1}{2} ln (2) = (x + 1) ln (9) : x = \frac{4 ln ( 3 ) - 5 ln ( 2 )}{3 ln ( 2 ) - 4 ln ( 3 )}

x = \frac{4 ln ( 3 ) - 5 ln ( 2 )}{3 ln ( 2 ) - 4 ln ( 3 )}

5^{x^{2}} = 2 5^{\frac{5}{2} x - 2}

2^{x} = 8^{x + 2}

(0.5)^{x} - 2^{x} - (0.5)^{2 x + 3} = 1

(x)^{x} = (x)^{x}

3^{2 x - 1} = 7^{x - 1}

What is the answer to sqrt(2^{3x+5)}=9^{x+1} ?
The answer to sqrt(2^{3x+5)}=9^{x+1} is x=(4ln(3)-5ln(2))/(3ln(2)-4ln(3))
Solve for x: sqrt(2^{3x+5)}=9^{x+1}
The solution is x=(4ln(3)-5ln(2))/(3ln(2)-4ln(3))