What is the answer to 3^{2x+2}+27^{x+1}=36 ?

The answer to 3^{2x+2}+27^{x+1}=36 is x=0

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3^{2x+2}+27^{x+1}=36

3^{2 x + 2} + 2 7^{x + 1} = 36

x = 0

Solution steps

3^{2 x + 2} + 2 7^{x + 1} = 36

Apply exponent rules

(3^{x})^{2} \cdot 3^{2} + (3^{x})^{3} \cdot 3^{3} = 36

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{2} + (u)^{3} \cdot 3^{3} = 36

Solve

u^{2} \cdot 3^{2} + u^{3} \cdot 3^{3} = 36 : u = 1

u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 1 : x = 0

x = 0

2^{x} + 2^{- x} = \frac{65}{8}

7^{3 x} - 5 \cdot 7^{x + 3} + 15 = 0

- 1 0^{- 9 b} = - 92.8

e^{x} \cdot e^{x} = e^{2} x

4^{x - 1} = 8

What is the answer to 3^{2x+2}+27^{x+1}=36 ?
The answer to 3^{2x+2}+27^{x+1}=36 is x=0
Solve for x: 3^{2x+2}+27^{x+1}=36
The solution is x=0