What is the answer to 4^{(x+3)}-4^{(x+2)}=24 ?

The answer to 4^{(x+3)}-4^{(x+2)}=24 is x=-1/2

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4^{(x+3)}-4^{(x+2)}=24

4^{(x + 3)} - 4^{(x + 2)} = 24

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4^{(x + 3)} - 4^{(x + 2)} = 24

Factor

4^{x + 3} - 4^{x + 2} : 3 \cdot 4^{x + 2}

3 \cdot 4^{x + 2} = 24

Divide both sides by

3

4^{x + 2} = 8

Apply exponent rules

2 (x + 2) = 3

Solve

2 (x + 2) = 3 : x = - \frac{1}{2}

x = - \frac{1}{2}

3^{x + 3} = 27

3^{x - 1} = 2^{x + 1}

3^{x} e^{7 x + 2} = 15

a^{2 x} = 2 + 1

2^{x} = 2^{2 x - 4}

What is the answer to 4^{(x+3)}-4^{(x+2)}=24 ?
The answer to 4^{(x+3)}-4^{(x+2)}=24 is x=-1/2
Solve for x: 4^{(x+3)}-4^{(x+2)}=24
The solution is x=-1/2