What is the answer to (2^{x+2})/(16)=sqrt(2) ?

The answer to (2^{x+2})/(16)=sqrt(2) is x= 5/2

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(2^{x+2})/(16)=sqrt(2)

\frac{2 ^{x + 2}}{16} = 2

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

\frac{2 ^{x + 2}}{16} = 2

Multiply both sides by

16

\frac{2 ^{x + 2}}{16} \cdot 16 = 2 \cdot 16

Simplify

2^{x + 2} = 2 \cdot 16

Apply exponent rules

x + 2 = \frac{9}{2}

Solve

x + 2 = \frac{9}{2} : x = \frac{5}{2}

x = \frac{5}{2}

2^{3 x} = \frac{1}{8}

3 \cdot 2^{2 x} - 18 (2^{x}) + 24 = 0

5 \cdot 6^{- 4 x + 3} - 3 = 11

2^{x + 4} \cdot \frac{1}{8 ^{x}} = 1

3^{2 x + 3} = 3^{(x^{2})}

What is the answer to (2^{x+2})/(16)=sqrt(2) ?
The answer to (2^{x+2})/(16)=sqrt(2) is x= 5/2
Solve for x: (2^{x+2})/(16)=sqrt(2)
The solution is x= 5/2