What are the solutions to the equation x^2+12x+36=0 ?

The solutions to the equation x^2+12x+36=0 are x=-6

Find the zeros of x^2+12x+36=0

The zeros of x^2+12x+36=0 are x=-6

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x^{2} + 12 x + 36 = 0

x = - 6

Solution steps

x^{2} + 12 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 36 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 1}

x = \frac{- 12}{2 \cdot 1}

\frac{- 12}{2 \cdot 1} = - 6

x = - 6

The solution to the quadratic equation is:

x = - 6

15 = π r + 2 r

x^{2} - 121 < 0

3 x^{2} - 192 = 0

e^{i x} - e^{- i x}

x + 2 = 4 - x^{2}

What are the solutions to the equation x^2+12x+36=0 ?
The solutions to the equation x^2+12x+36=0 are x=-6
Find the zeros of x^2+12x+36=0
The zeros of x^2+12x+36=0 are x=-6