What is the answer to 5(5^{2x})-26(5^x)+5=0 ?

The answer to 5(5^{2x})-26(5^x)+5=0 is x=1,x=-1

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5(5^{2x})-26(5^x)+5=0

5 (5^{2 x}) - 26 (5^{x}) + 5 = 0

x = 1, x = - 1

Solution steps

5 (5^{2 x}) - 26 (5^{x}) + 5 = 0

Apply exponent rules

(5^{x})^{2} \cdot 5^{1} - 26 \cdot 5^{x} + 5 = 0

Rewrite the equation with

5^{x} = u

(u)^{2} \cdot 5^{1} - 26 u + 5 = 0

Solve

u^{2} \cdot 5^{1} - 26 u + 5 = 0 : u = 5, u = \frac{1}{5}

u = 5, u = \frac{1}{5}

Substitute back

u = 5^{x},

solve for

x

Solve

5^{x} = 5 : x = 1

Solve

5^{x} = \frac{1}{5} : x = - 1

x = 1, x = - 1

\frac{13}{2 + e ^{x}} = 4

7^{6 x + 7} = 3

6^{x} - 28 = - 8

1500 = 159 + 28 e^{0.02 t}

4 = 1 0^{x}

What is the answer to 5(5^{2x})-26(5^x)+5=0 ?
The answer to 5(5^{2x})-26(5^x)+5=0 is x=1,x=-1
Solve for x: 5(5^{2x})-26(5^x)+5=0
The solution is x=1,x=-1