What is the answer to 3^{4-5x}=2^{x+4} ?

The answer to 3^{4-5x}=2^{x+4} is x=(4ln(3)-4ln(2))/(ln(486))

Solve for x: 3^{4-5x}=2^{x+4}

The solution is x=(4ln(3)-4ln(2))/(ln(486))

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3^{4 - 5 x} = 2^{x + 4}

x = \frac{4 ln ( 3 ) - 4 ln ( 2 )}{ln ( 486 )}

Decimal Notation

x = 0.26217 \dots

Solution steps

3^{4 - 5 x} = 2^{x + 4}

Apply exponent rules

(4 - 5 x) ln (3) = (x + 4) ln (2)

Solve

(4 - 5 x) ln (3) = (x + 4) ln (2) : x = \frac{4 ln ( 3 ) - 4 ln ( 2 )}{ln ( 486 )}

x = \frac{4 ln ( 3 ) - 4 ln ( 2 )}{ln ( 486 )}

2^{5 x + 5} + 2^{5 x + 1} = 17

e^{- x} (x^{2} - 5 x + 2) = 0

y, 2^{x + y} = x

2 5^{x - 3} = (\frac{1}{125})^{x + 2}

(5^{x})^{2} - 26 (5^{x}) + 25 = 0

What is the answer to 3^{4-5x}=2^{x+4} ?
The answer to 3^{4-5x}=2^{x+4} is x=(4ln(3)-4ln(2))/(ln(486))
Solve for x: 3^{4-5x}=2^{x+4}
The solution is x=(4ln(3)-4ln(2))/(ln(486))