What is the answer to sqrt(3^{2x-2)}=9^{3x+2} ?

The answer to sqrt(3^{2x-2)}=9^{3x+2} is x=-1

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sqrt(3^{2x-2)}=9^{3x+2}

3^{2 x - 2} = 9^{3 x + 2}

x = - 1

Solution steps

3^{2 x - 2} = 9^{3 x + 2}

Apply exponent rules

x - 1 = 2 (3 x + 2)

Solve

x - 1 = 2 (3 x + 2) : x = - 1

x = - 1

2^{2 x} \cdot 5^{x} = 8000

(\frac{5}{4})^{x} = 1650.35

2^{x} = 1048576

100 = 2580 (0.94)^{x} - 180

x, e^{x y + 1} = 5

What is the answer to sqrt(3^{2x-2)}=9^{3x+2} ?
The answer to sqrt(3^{2x-2)}=9^{3x+2} is x=-1
Solve for x: sqrt(3^{2x-2)}=9^{3x+2}
The solution is x=-1