What is the answer to 9^{(4x-5)}=25^{(6x+2)} ?

The answer to 9^{(4x-5)}=25^{(6x+2)} is x=(4ln(5)+10ln(3))/(4(2ln(3)-3ln(5)))

Solve for x: 9^{(4x-5)}=25^{(6x+2)}

The solution is x=(4ln(5)+10ln(3))/(4(2ln(3)-3ln(5)))

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9^{(4 x - 5)} = 2 5^{(6 x + 2)}

x = \frac{4 ln ( 5 ) + 10 ln ( 3 )}{4 ( 2 ln ( 3 ) - 3 ln ( 5 ) )}

Solution steps

9^{(4 x - 5)} = 2 5^{(6 x + 2)}

Apply exponent rules

(4 x - 5) ln (9) = (6 x + 2) ln (25)

Solve

(4 x - 5) ln (9) = (6 x + 2) ln (25) : x = \frac{4 ln ( 5 ) + 10 ln ( 3 )}{4 ( 2 ln ( 3 ) - 3 ln ( 5 ) )}

x = \frac{4 ln ( 5 ) + 10 ln ( 3 )}{4 ( 2 ln ( 3 ) - 3 ln ( 5 ) )}

e^{3 x} = \frac{1}{64}

7^{x - 1} = 3^{x + 1}

e^{x} - 2 e^{- x} = 0

x, 4^{x} = 5

y, x = y e^{y}

What is the answer to 9^{(4x-5)}=25^{(6x+2)} ?
The answer to 9^{(4x-5)}=25^{(6x+2)} is x=(4ln(5)+10ln(3))/(4(2ln(3)-3ln(5)))
Solve for x: 9^{(4x-5)}=25^{(6x+2)}
The solution is x=(4ln(5)+10ln(3))/(4(2ln(3)-3ln(5)))