What is the answer to 2^{x+1}+2^{x+3}=320 ?

The answer to 2^{x+1}+2^{x+3}=320 is x=5

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2^{x+1}+2^{x+3}=320

2^{x + 1} + 2^{x + 3} = 320

x = 5

Solution steps

2^{x + 1} + 2^{x + 3} = 320

Factor

2^{x + 1} + 2^{x + 3} : 5 \cdot 2^{x + 1}

5 \cdot 2^{x + 1} = 320

Divide both sides by

5

2^{x + 1} = 64

Apply exponent rules

x + 1 = 6

Solve

x + 1 = 6 : x = 5

x = 5

3^{x + 2} = 3^{7}

e^{x} - 3 e^{- x} = 2

5^{x} + 5 = 2 \cdot 5^{2 - x}

e^{x} - 6 e^{- x} + 1 = 0

3 \cdot 3^{x} = 27

What is the answer to 2^{x+1}+2^{x+3}=320 ?
The answer to 2^{x+1}+2^{x+3}=320 is x=5
Solve for x: 2^{x+1}+2^{x+3}=320
The solution is x=5