What are the solutions to the equation x^2+4x-21=0 ?

The solutions to the equation x^2+4x-21=0 are x=3,x=-7

Find the zeros of x^2+4x-21=0

The zeros of x^2+4x-21=0 are x=3,x=-7

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x^{2} + 4 x - 21 = 0

x = 3, x = - 7

Solution steps

x^{2} + 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 10}{2 \cdot 1}

x = \frac{- 4 + 10}{2 \cdot 1} : 3

x = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

2 + \frac{5}{x} > 1

- x + 9 x = 32

x^{2} - 7 < 0

∣ 2 x + 3 ∣ > 8

\frac{3 6}{6}

What are the solutions to the equation x^2+4x-21=0 ?
The solutions to the equation x^2+4x-21=0 are x=3,x=-7
Find the zeros of x^2+4x-21=0
The zeros of x^2+4x-21=0 are x=3,x=-7