What is the answer to 4*3^{x+1}-9^x=27 ?

The answer to 4*3^{x+1}-9^x=27 is x=1,x=2

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4*3^{x+1}-9^x=27

4 \cdot 3^{x + 1} - 9^{x} = 27

x = 1, x = 2

Solution steps

4 \cdot 3^{x + 1} - 9^{x} = 27

Apply exponent rules

4 \cdot 3^{x} \cdot 3^{1} - (3^{x})^{2} = 27

Rewrite the equation with

3^{x} = u

4 u \cdot 3^{1} - (u)^{2} = 27

Solve

4 u \cdot 3^{1} - u^{2} = 27 : u = 3, u = 9

u = 3, u = 9

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 3 : x = 1

Solve

3^{x} = 9 : x = 2

x = 1, x = 2

100 = 200 e^{- 0.06 x}

x^{2} e^{- x} = x e^{- x}

7^{2 - x} - 4 9^{2 - x} + 42 = 0

- \frac{1}{81} = - 3^{x}

9^{- x + 5} = 2 7^{6 x - 10}

What is the answer to 4*3^{x+1}-9^x=27 ?
The answer to 4*3^{x+1}-9^x=27 is x=1,x=2
Solve for x: 4*3^{x+1}-9^x=27
The solution is x=1,x=2