What is the answer to 2^{x+5}+2^{x+4}+2^{x+3}=28 ?

The answer to 2^{x+5}+2^{x+4}+2^{x+3}=28 is x=-1

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2^{x+5}+2^{x+4}+2^{x+3}=28

2^{x + 5} + 2^{x + 4} + 2^{x + 3} = 28

x = - 1

Solution steps

2^{x + 5} + 2^{x + 4} + 2^{x + 3} = 28

Factor

2^{x + 5} + 2^{x + 4} + 2^{x + 3} : 7 \cdot 2^{x + 3}

7 \cdot 2^{x + 3} = 28

Divide both sides by

7

2^{x + 3} = 4

Apply exponent rules

x + 3 = 2

Solve

x + 3 = 2 : x = - 1

x = - 1

12 = 25 e^{- (\frac{1}{5}) p}

x, 1 0^{x} = 38 z

9^{- x} = \frac{1}{3}

0. 5^{x + 4} = 1

5^{b} = 125

What is the answer to 2^{x+5}+2^{x+4}+2^{x+3}=28 ?
The answer to 2^{x+5}+2^{x+4}+2^{x+3}=28 is x=-1
Solve for x: 2^{x+5}+2^{x+4}+2^{x+3}=28
The solution is x=-1