What is the answer to 9^{3^{4x}}=27^{4^{2x}} ?

The answer to 9^{3^{4x}}=27^{4^{2x}} is x= 1/4

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9^{3^{4x}}=27^{4^{2x}}

9^{3^{4 x}} = 2 7^{4^{2 x}}

x = \frac{1}{4}

Solution steps

9^{3^{4 x}} = 2 7^{4^{2 x}}

Apply exponent rules

ln (2) + 4 x ln (3) = ln (3) + 2 x ln (4)

Solve

ln (2) + 4 x ln (3) = ln (3) + 2 x ln (4) : x = \frac{1}{4}

x = \frac{1}{4}

5^{x} = 29

(e^{p})^{3} = 3 e^{p}

5^{x} = 94

4^{x} = e^{5 x - 1}

e^{x} = - e^{- x}

What is the answer to 9^{3^{4x}}=27^{4^{2x}} ?
The answer to 9^{3^{4x}}=27^{4^{2x}} is x= 1/4
Solve for x: 9^{3^{4x}}=27^{4^{2x}}
The solution is x= 1/4