What is the answer to 3^{x-1}+3^x+3^{x+1}=117 ?

The answer to 3^{x-1}+3^x+3^{x+1}=117 is x=3

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3^{x-1}+3^x+3^{x+1}=117

3^{x - 1} + 3^{x} + 3^{x + 1} = 117

x = 3

Solution steps

3^{x - 1} + 3^{x} + 3^{x + 1} = 117

Factor

3^{x - 1} + 3^{x} + 3^{x + 1} : 13 \cdot 3^{x - 1}

13 \cdot 3^{x - 1} = 117

Divide both sides by

13

3^{x - 1} = 9

Apply exponent rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

2^{2} n = 4^{n}

e^{k} = 2

e^{x} = e^{- 4 x}

x, e^{e^{x}} = 10

4096 = 2^{n}

What is the answer to 3^{x-1}+3^x+3^{x+1}=117 ?
The answer to 3^{x-1}+3^x+3^{x+1}=117 is x=3
Solve for x: 3^{x-1}+3^x+3^{x+1}=117
The solution is x=3