What is the answer to 2^x*2^{3x-8}=6 ?

The answer to 2^x*2^{3x-8}=6 is x=(ln(1536))/(4ln(2))

Solve for x: 2^x*2^{3x-8}=6

The solution is x=(ln(1536))/(4ln(2))

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2^{x} \cdot 2^{3 x - 8} = 6

x = \frac{ln ( 1536 )}{4 ln ( 2 )}

Decimal Notation

x = 2.64624 \dots

Solution steps

2^{x} \cdot 2^{3 x - 8} = 6

Apply exponent rules

(x + 3 x - 8) ln (2) = ln (6)

Solve

(x + 3 x - 8) ln (2) = ln (6) : x = \frac{ln ( 1536 )}{4 ln ( 2 )}

x = \frac{ln ( 1536 )}{4 ln ( 2 )}

a^{x} = b c

2^{x} - 2 = - 2 x + 12

7^{x - 2} = 49

22000 e^{0.05 t} = 11000 e^{0.07 t}

1 6^{x} = 8^{6}

What is the answer to 2^x*2^{3x-8}=6 ?
The answer to 2^x*2^{3x-8}=6 is x=(ln(1536))/(4ln(2))
Solve for x: 2^x*2^{3x-8}=6
The solution is x=(ln(1536))/(4ln(2))