What are the solutions to the equation x^2+10x-414=0 ?

The solutions to the equation x^2+10x-414=0 are x=-5+sqrt(439),x=-5-sqrt(439)

Find the zeros of x^2+10x-414=0

The zeros of x^2+10x-414=0 are x=-5+sqrt(439),x=-5-sqrt(439)

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x^{2} + 10 x - 414 = 0

x = - 5 + 439, x = - 5 - 439

Decimal Notation

x = 15.95232 \dots, x = - 25.95232 \dots

Solution steps

x^{2} + 10 x - 414 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 414 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 414) = 2439

x_{1, 2} = \frac{- 10 \pm 2 439}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 439}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 439}{2 \cdot 1}

x = \frac{- 10 + 2 439}{2 \cdot 1} : - 5 + 439

x = \frac{- 10 - 2 439}{2 \cdot 1} : - 5 - 439

The solutions to the quadratic equation are:

x = - 5 + 439, x = - 5 - 439

4 x + 8 = 2 (x + 1)

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\frac{2 - i}{2 + i}

x^{2} + 19 x + 90 x

x^{2} + 13 = - 7 x

What are the solutions to the equation x^2+10x-414=0 ?
The solutions to the equation x^2+10x-414=0 are x=-5+sqrt(439),x=-5-sqrt(439)
Find the zeros of x^2+10x-414=0
The zeros of x^2+10x-414=0 are x=-5+sqrt(439),x=-5-sqrt(439)