What is the answer to 5^{2x-1}=4^{x+3} ?

The answer to 5^{2x-1}=4^{x+3} is x=(ln(320))/(2(ln(5)-ln(2)))

Solve for x: 5^{2x-1}=4^{x+3}

The solution is x=(ln(320))/(2(ln(5)-ln(2)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{2 x - 1} = 4^{x + 3}

x = \frac{ln ( 320 )}{2 ( ln ( 5 ) - ln ( 2 ) )}

Decimal Notation

x = 3.14764 \dots

Solution steps

5^{2 x - 1} = 4^{x + 3}

Apply exponent rules

(2 x - 1) ln (5) = (x + 3) ln (4)

Solve

(2 x - 1) ln (5) = (x + 3) ln (4) : x = \frac{ln ( 320 )}{2 ( ln ( 5 ) - ln ( 2 ) )}

x = \frac{ln ( 320 )}{2 ( ln ( 5 ) - ln ( 2 ) )}

280 = 1400 - 1400 (0.9)^{t}

3^{x} = 33

200 e^{0.063 t} = 600

3 (2^{x + 4}) = 350

e^{- 3 t} = 0

What is the answer to 5^{2x-1}=4^{x+3} ?
The answer to 5^{2x-1}=4^{x+3} is x=(ln(320))/(2(ln(5)-ln(2)))
Solve for x: 5^{2x-1}=4^{x+3}
The solution is x=(ln(320))/(2(ln(5)-ln(2)))