What is the answer to 2^{x-1}+2^{x-2}=6 ?

The answer to 2^{x-1}+2^{x-2}=6 is x=3

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2^{x-1}+2^{x-2}=6

2^{x - 1} + 2^{x - 2} = 6

x = 3

Solution steps

2^{x - 1} + 2^{x - 2} = 6

Factor

2^{x - 1} + 2^{x - 2} : 3 \cdot 2^{x - 2}

3 \cdot 2^{x - 2} = 6

Divide both sides by

3

2^{x - 2} = 2

Apply exponent rules

x - 2 = 1

Solve

x - 2 = 1 : x = 3

x = 3

2^{2 n} = 4^{n}

12 x \cdot 3^{x + 1} = 648

2 7^{x + 5} = 81

6 \cdot 2^{x} = 14

5 + e^{x} = - \frac{x}{2} + 2

What is the answer to 2^{x-1}+2^{x-2}=6 ?
The answer to 2^{x-1}+2^{x-2}=6 is x=3
Solve for x: 2^{x-1}+2^{x-2}=6
The solution is x=3