What is the answer to 79=25^x ?

The answer to 79=25^x is x=(ln(79))/(2ln(5))

The solution is x=(ln(79))/(2ln(5))

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79=25^x

79 = 2 5^{x}

x = \frac{ln ( 79 )}{2 ln ( 5 )}

Decimal Notation

x = 1.35744 \dots

Solution steps

79 = 2 5^{x}

Apply exponent rules

ln (79) = x ln (25)

Solve

ln (79) = x ln (25) : x = \frac{ln ( 79 )}{2 ln ( 5 )}

x = \frac{ln ( 79 )}{2 ln ( 5 )}

3^{3 + 1} = 3^{- x}

64 = 2^{n}

6^{a} \cdot 2^{b} = 3^{x}

8.1 = 1.1 2^{x - 3} + 2

2 e^{x} + x e^{x} = 0