What is the answer to 4^{x+1}+4^{x-1}=34 ?

The answer to 4^{x+1}+4^{x-1}=34 is x= 3/2

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4^{x+1}+4^{x-1}=34

4^{x + 1} + 4^{x - 1} = 34

x = \frac{3}{2}

Solution steps

4^{x + 1} + 4^{x - 1} = 34

Factor

4^{x + 1} + 4^{x - 1} : 17 \cdot 4^{x - 1}

17 \cdot 4^{x - 1} = 34

Divide both sides by

17

4^{x - 1} = 2

Apply exponent rules

2 (x - 1) = 1

Solve

2 (x - 1) = 1 : x = \frac{3}{2}

x = \frac{3}{2}

2. 5^{x} + 4 = 1254

2^{x} - 2 \cdot 4^{x} = 0

e^{- 4 x} = 0

291 6^{x} = 54

3^{x} + 3^{x + 2} = 81

What is the answer to 4^{x+1}+4^{x-1}=34 ?
The answer to 4^{x+1}+4^{x-1}=34 is x= 3/2
Solve for x: 4^{x+1}+4^{x-1}=34
The solution is x= 3/2