What is the answer to 2500=2000(1.04)^t ?

The answer to 2500=2000(1.04)^t is t=(ln(5/4))/(ln(1.04))

Solve for t: 2500=2000(1.04)^t

The solution is t=(ln(5/4))/(ln(1.04))

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2500 = 2000 (1.04)^{t}

t = \frac{ln ( \frac{5}{4} )}{ln ( 1.04 )}

Decimal Notation

t = 5.68943 \dots

Solution steps

2500 = 2000 (1.04)^{t}

Switch sides

2000 \cdot 1.0 4^{t} = 2500

Divide both sides by

2000

1.0 4^{t} = \frac{5}{4}

Apply exponent rules

t ln (1.04) = ln (\frac{5}{4})

Solve

t ln (1.04) = ln (\frac{5}{4}) : t = \frac{ln ( \frac{5}{4} )}{ln ( 1.04 )}

t = \frac{ln ( \frac{5}{4} )}{ln ( 1.04 )}

x, 30 = 1 0^{x}

5 e^{6 k} = 44

(\frac{1}{4})^{x} = 8^{x + 1}

5 e^{2 x} = 3

5^{x + 1} + 5^{x} = 750

What is the answer to 2500=2000(1.04)^t ?
The answer to 2500=2000(1.04)^t is t=(ln(5/4))/(ln(1.04))
Solve for t: 2500=2000(1.04)^t
The solution is t=(ln(5/4))/(ln(1.04))