What is the answer to 2^{1-x}=3^{2x+5} ?

The answer to 2^{1-x}=3^{2x+5} is x=-(5ln(3)-ln(2))/(ln(18))

Solve for x: 2^{1-x}=3^{2x+5}

The solution is x=-(5ln(3)-ln(2))/(ln(18))

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2^{1 - x} = 3^{2 x + 5}

x = - \frac{5 ln ( 3 ) - ln ( 2 )}{ln ( 18 )}

Solution steps

2^{1 - x} = 3^{2 x + 5}

Apply exponent rules

(1 - x) ln (2) = (2 x + 5) ln (3)

Solve

(1 - x) ln (2) = (2 x + 5) ln (3) : x = - \frac{5 ln ( 3 ) - ln ( 2 )}{ln ( 18 )}

x = - \frac{5 ln ( 3 ) - ln ( 2 )}{ln ( 18 )}

e^{2 x - 3} = 75

3^{2 x} - 5 \cdot 3^{x} - 36 = 0

2^{x^{2} - 2 x + 1} = 1

3 \cdot 2^{x + 2} - 5 \cdot 2^{x} = 56

e^{x + 1} = 3

What is the answer to 2^{1-x}=3^{2x+5} ?
The answer to 2^{1-x}=3^{2x+5} is x=-(5ln(3)-ln(2))/(ln(18))
Solve for x: 2^{1-x}=3^{2x+5}
The solution is x=-(5ln(3)-ln(2))/(ln(18))