What is the answer to x^{2/(log_{x)(2x)}}=2 ?

The answer to x^{2/(log_{x)(2x)}}=2 is x=2,x= 1/(e^{\frac{ln(2)){2}}}

Solve for x: x^{2/(log_{x)(2x)}}=2

The solution is x=2,x= 1/(e^{\frac{ln(2)){2}}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{\frac{2}{l o g _{x} ( 2 x )}} = 2

x = 2, x = \frac{1}{e ^{\frac{l n ( 2 )}{2}}}

Solution steps

x^{\frac{2}{l o g _{x} ( 2 x )}} = 2

Apply exponent rules

\frac{2}{lo g _{x} ( 2 x )} ln (x) = ln (2)

Solve

\frac{2}{lo g _{x} ( 2 x )} ln (x) = ln (2) : x = 2, x = \frac{1}{e ^{\frac{l n ( 2 )}{2}}}

x = 2, x = \frac{1}{e ^{\frac{l n ( 2 )}{2}}}

Verify Solutions:

x = 2

True

, x = \frac{1}{e ^{\frac{l n ( 2 )}{2}}}

True

The solutions are

x = 2, x = \frac{1}{e ^{\frac{l n ( 2 )}{2}}}

4 e^{- t} + t = 0

2^{x} \cdot 8 = 4^{x + 1}

7^{3 x - 2} = 1 0^{2 x}

2 5^{x + 3} = 12 5^{x}

4^{x + 5} = 6

What is the answer to x^{2/(log_{x)(2x)}}=2 ?
The answer to x^{2/(log_{x)(2x)}}=2 is x=2,x= 1/(e^{\frac{ln(2)){2}}}
Solve for x: x^{2/(log_{x)(2x)}}=2
The solution is x=2,x= 1/(e^{\frac{ln(2)){2}}}