What is the answer to 5(me^{mx})=2(e^{mx}) ?

The answer to 5(me^{mx})=2(e^{mx}) is No Solution for x\in\mathbb{R}

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5(me^{mx})=2(e^{mx})

5 (m e^{m x}) = 2 (e^{m x})

No Solution for x \in R

Solution steps

5 (m e^{m x}) = 2 (e^{m x})

Move

2 e^{m x}

to the left side

5 m e^{m x} - 2 e^{m x} = 0

Factor

5 m e^{m x} - 2 e^{m x} : e^{m x} (5 m - 2)

e^{m x} (5 m - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

e^{m x} = 0

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

729 = 3^{n - 1}

0 = 2^{x + 1}

2 5^{y} = 125

2^{4 x} + 64 = 20 (2^{2 x})

e^{7 - 4 x} = 4

What is the answer to 5(me^{mx})=2(e^{mx}) ?
The answer to 5(me^{mx})=2(e^{mx}) is No Solution for x\in\mathbb{R}