What is the answer to 2^{8^{x-2}}=4^{4^{x-1}} ?

The answer to 2^{8^{x-2}}=4^{4^{x-1}} is x=5

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2^{8^{x-2}}=4^{4^{x-1}}

2^{8^{x - 2}} = 4^{4^{x - 1}}

x = 5

Solution steps

2^{8^{x - 2}} = 4^{4^{x - 1}}

Apply exponent rules

3 (x - 2) = 1 + 2 (x - 1)

Solve

3 (x - 2) = 1 + 2 (x - 1) : x = 5

x = 5

4^{2 x + 1} - 65 (4^{x}) + 16 = 0

e^{(9 x)} - 5 e^{(3 x)} + 4 = 0

2^{3 x - 8} = 16

x^{(\frac{0.72}{( x - 1 )})} = 2

3^{x^{3}} = 24 3^{3}

What is the answer to 2^{8^{x-2}}=4^{4^{x-1}} ?
The answer to 2^{8^{x-2}}=4^{4^{x-1}} is x=5
Solve for x: 2^{8^{x-2}}=4^{4^{x-1}}
The solution is x=5