What is the answer to 65.33=16+54^{-k(5)} ?

The answer to 65.33=16+54^{-k(5)} is k=-(ln(49.33))/(5ln(54))

Solve for k: 65.33=16+54^{-k(5)}

The solution is k=-(ln(49.33))/(5ln(54))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

65.33 = 16 + 5 4^{- k (5)}

k = - \frac{ln ( 49.33 )}{5 ln ( 54 )}

Solution steps

65.33 = 16 + 5 4^{- k (5)}

Switch sides

16 + 5 4^{- k 5} = 65.33

Move

16

to the right side

5 4^{- k 5} = 49.33

Apply exponent rules

- k \cdot 5 ln (54) = ln (49.33)

Solve

- k \cdot 5 ln (54) = ln (49.33) : k = - \frac{ln ( 49.33 )}{5 ln ( 54 )}

k = - \frac{ln ( 49.33 )}{5 ln ( 54 )}

2^{2 x - 3} = 16

e^{x + 1} = 2^{x + 2}

2^{n} = 4

2^{1 + x} = 5^{x}

3 x^{2} e^{x} + x^{3} e^{x} = 0

What is the answer to 65.33=16+54^{-k(5)} ?
The answer to 65.33=16+54^{-k(5)} is k=-(ln(49.33))/(5ln(54))
Solve for k: 65.33=16+54^{-k(5)}
The solution is k=-(ln(49.33))/(5ln(54))