What is the answer to 2=(1+(0.065)/(12))^{12t} ?

The answer to 2=(1+(0.065)/(12))^{12t} is t=(ln(2))/(12ln(\frac{12.065){12})}

Solve for t: 2=(1+(0.065)/(12))^{12t}

The solution is t=(ln(2))/(12ln(\frac{12.065){12})}

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2 = (1 + \frac{0.065}{12})^{12 t}

t = \frac{ln ( 2 )}{12 ln ( \frac{12.065}{12} )}

Solution steps

2 = (1 + \frac{0.065}{12})^{12 t}

Apply exponent rules

ln (2) = 12 t ln (1 + \frac{0.065}{12})

Solve

ln (2) = 12 t ln (1 + \frac{0.065}{12}) : t = \frac{ln ( 2 )}{12 ln ( \frac{12.065}{12} )}

t = \frac{ln ( 2 )}{12 ln ( \frac{12.065}{12} )}

1 0^{x} = 1500

n, a^{n} = a

x^{x} = 1 0^{36 \cdot 1 0^{9}}

k, k^{2} t^{k} = 0

2 e^{(x + 6)} = 20

What is the answer to 2=(1+(0.065)/(12))^{12t} ?
The answer to 2=(1+(0.065)/(12))^{12t} is t=(ln(2))/(12ln(\frac{12.065){12})}
Solve for t: 2=(1+(0.065)/(12))^{12t}
The solution is t=(ln(2))/(12ln(\frac{12.065){12})}