What is the answer to 2^{x+2}=3^x ?

The answer to 2^{x+2}=3^x is x=(2ln(2))/(ln(3)-ln(2))

Solve for x: 2^{x+2}=3^x

The solution is x=(2ln(2))/(ln(3)-ln(2))

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2^{x + 2} = 3^{x}

x = \frac{2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

Solution steps

2^{x + 2} = 3^{x}

Apply exponent rules

(x + 2) ln (2) = x ln (3)

Solve

(x + 2) ln (2) = x ln (3) : x = \frac{2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

- 3 e^{2 x} + 16 = 5

4^{2 x + 1} = 32

417 e^{x} = 3888

2^{2 x - 1} = 32

What is the answer to 2^{x+2}=3^x ?
The answer to 2^{x+2}=3^x is x=(2ln(2))/(ln(3)-ln(2))
Solve for x: 2^{x+2}=3^x
The solution is x=(2ln(2))/(ln(3)-ln(2))