What is the answer to 3^{x-4}=2 ?

The answer to 3^{x-4}=2 is x=(ln(2))/(ln(3))+4

Solve for x: 3^{x-4}=2

The solution is x=(ln(2))/(ln(3))+4

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3^{x - 4} = 2

x = \frac{ln ( 2 )}{ln ( 3 )} + 4

Solution steps

3^{x - 4} = 2

Apply exponent rules

(x - 4) ln (3) = ln (2)

Solve

(x - 4) ln (3) = ln (2) : x = \frac{ln ( 2 )}{ln ( 3 )} + 4

x = \frac{ln ( 2 )}{ln ( 3 )} + 4

6 4^{x} = 256

2^{2000} = 3 2^{x}

e^{x} = 0.6

13 (1 + e^{- x})^{- 1} = 2

4^{x + 1} = (\frac{1}{2})^{- 3 x}

What is the answer to 3^{x-4}=2 ?
The answer to 3^{x-4}=2 is x=(ln(2))/(ln(3))+4
Solve for x: 3^{x-4}=2
The solution is x=(ln(2))/(ln(3))+4