What is the answer to 4^{2x^2}= 1/(16^{3x-1)} ?

The answer to 4^{2x^2}= 1/(16^{3x-1)} is x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2

Solve for x: 4^{2x^2}= 1/(16^{3x-1)}

The solution is x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2

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4^{2 x^{2}} = \frac{1}{1 6 ^{3 x - 1}}

x = \frac{- 3 + 13}{2}, x = - \frac{3 + 13}{2}

Solution steps

4^{2 x^{2}} = \frac{1}{1 6 ^{3 x - 1}}

Apply exponent rules

2 x^{2} = 2 (- 3 x + 1)

Solve

2 x^{2} = 2 (- 3 x + 1) : x = \frac{- 3 + 13}{2}, x = - \frac{3 + 13}{2}

x = \frac{- 3 + 13}{2}, x = - \frac{3 + 13}{2}

Verify Solutions:

x = \frac{- 3 + 13}{2}

True

, x = - \frac{3 + 13}{2}

True

The solutions are

x = \frac{- 3 + 13}{2}, x = - \frac{3 + 13}{2}

2^{x} \cdot 4^{2 - x} = 8

6 4^{x} = 1 6^{x - 1}

i, x^{2 i} - 2 x^{i} + 2 = 0

e^{x} = 20.0855

\frac{e ^{x} - e ^{- x}}{2} = 1

What is the answer to 4^{2x^2}= 1/(16^{3x-1)} ?
The answer to 4^{2x^2}= 1/(16^{3x-1)} is x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2
Solve for x: 4^{2x^2}= 1/(16^{3x-1)}
The solution is x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2