What is the answer to 10^{-x}=5^{x-1} ?

The answer to 10^{-x}=5^{x-1} is x=(ln(5))/(ln(50))

Solve for x: 10^{-x}=5^{x-1}

The solution is x=(ln(5))/(ln(50))

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1 0^{- x} = 5^{x - 1}

x = \frac{ln ( 5 )}{ln ( 50 )}

Solution steps

1 0^{- x} = 5^{x - 1}

Apply exponent rules

- x ln (10) = (x - 1) ln (5)

Solve

- x ln (10) = (x - 1) ln (5) : x = \frac{ln ( 5 )}{ln ( 50 )}

x = \frac{ln ( 5 )}{ln ( 50 )}

y, x^{y} + e^{x} = a

3^{2 x + 2} + 17 \cdot 3^{x} = 2

9^{x} - 90 \cdot 3^{x} + 729 = 0

5 e^{x} = 1

x, 3^{x} = 10

What is the answer to 10^{-x}=5^{x-1} ?
The answer to 10^{-x}=5^{x-1} is x=(ln(5))/(ln(50))
Solve for x: 10^{-x}=5^{x-1}
The solution is x=(ln(5))/(ln(50))