What are the solutions to the equation 7x^2-13x-28=x^2-27 ?

The solutions to the equation 7x^2-13x-28=x^2-27 are x=(13+sqrt(193))/(12),x=(13-sqrt(193))/(12)

Find the zeros of 7x^2-13x-28=x^2-27

The zeros of 7x^2-13x-28=x^2-27 are x=(13+sqrt(193))/(12),x=(13-sqrt(193))/(12)

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7 x^{2} - 13 x - 28 = x^{2} - 27

x = \frac{13 + 193}{12}, x = \frac{13 - 193}{12}

Decimal Notation

x = 2.24103 \dots, x = - 0.07437 \dots

Solution steps

7 x^{2} - 13 x - 28 = x^{2} - 27

Move

27

to the left side

7 x^{2} - 13 x - 1 = x^{2}

Move

x^{2}

to the left side

6 x^{2} - 13 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 13)^{2} - 4 \cdot 6 (- 1) = 193

x_{1, 2} = \frac{- ( - 13 ) \pm 193}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 193}{2 \cdot 6}, x_{2} = \frac{- ( - 13 ) - 193}{2 \cdot 6}

x = \frac{- ( - 13 ) + 193}{2 \cdot 6} : \frac{13 + 193}{12}

x = \frac{- ( - 13 ) - 193}{2 \cdot 6} : \frac{13 - 193}{12}

The solutions to the quadratic equation are:

x = \frac{13 + 193}{12}, x = \frac{13 - 193}{12}

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5 x - 6 x - 5 = - 7 x

2.5 - 0.25 x = - 3

What are the solutions to the equation 7x^2-13x-28=x^2-27 ?
The solutions to the equation 7x^2-13x-28=x^2-27 are x=(13+sqrt(193))/(12),x=(13-sqrt(193))/(12)
Find the zeros of 7x^2-13x-28=x^2-27
The zeros of 7x^2-13x-28=x^2-27 are x=(13+sqrt(193))/(12),x=(13-sqrt(193))/(12)