What is the answer to 9^{3x+1}=6 ?

The answer to 9^{3x+1}=6 is x=(ln(2/3))/(6ln(3))

Solve for x: 9^{3x+1}=6

The solution is x=(ln(2/3))/(6ln(3))

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9^{3 x + 1} = 6

x = \frac{ln ( \frac{2}{3} )}{6 ln ( 3 )}

Decimal Notation

x = - 0.06151 \dots

Solution steps

9^{3 x + 1} = 6

Apply exponent rules

(3 x + 1) ln (9) = ln (6)

Solve

(3 x + 1) ln (9) = ln (6) : x = \frac{ln ( \frac{2}{3} )}{6 ln ( 3 )}

x = \frac{ln ( \frac{2}{3} )}{6 ln ( 3 )}

2 e^{- x} - e^{x} + 1 = 0

2^{x} - 2^{x + 2} = - 12

3^{3 x - 2} = 15

z, 2 = e^{2 x + 2 y + z}

2^{(7 x - 9)} = 4^{6 x}

What is the answer to 9^{3x+1}=6 ?
The answer to 9^{3x+1}=6 is x=(ln(2/3))/(6ln(3))
Solve for x: 9^{3x+1}=6
The solution is x=(ln(2/3))/(6ln(3))