What is the answer to 5^{x-4}=7 ?

The answer to 5^{x-4}=7 is x=(ln(7))/(ln(5))+4

Solve for x: 5^{x-4}=7

The solution is x=(ln(7))/(ln(5))+4

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5^{x - 4} = 7

x = \frac{ln ( 7 )}{ln ( 5 )} + 4

Solution steps

5^{x - 4} = 7

Apply exponent rules

(x - 4) ln (5) = ln (7)

Solve

(x - 4) ln (5) = ln (7) : x = \frac{ln ( 7 )}{ln ( 5 )} + 4

x = \frac{ln ( 7 )}{ln ( 5 )} + 4

4^{3 x - 1} = 3 2^{x + 6}

(27)^{2 x + 1} = \frac{1}{3}

2^{2 x - 2} = 1

e^{x} = 99

27 \cdot 3^{2 x + 3} = 9^{3 x}

What is the answer to 5^{x-4}=7 ?
The answer to 5^{x-4}=7 is x=(ln(7))/(ln(5))+4
Solve for x: 5^{x-4}=7
The solution is x=(ln(7))/(ln(5))+4