What is the answer to 27^{x+2}=9^{6x+10} ?

The answer to 27^{x+2}=9^{6x+10} is x=-14/9

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27^{x+2}=9^{6x+10}

2 7^{x + 2} = 9^{6 x + 10}

x = - \frac{14}{9}

Solution steps

2 7^{x + 2} = 9^{6 x + 10}

Apply exponent rules

3 (x + 2) = 2 (6 x + 10)

Solve

3 (x + 2) = 2 (6 x + 10) : x = - \frac{14}{9}

x = - \frac{14}{9}

b^{7 - x} = b^{3}

12 5^{x + 1} = 25

\frac{1}{2} = e^{- t}

1 0^{x} = 25.6

9^{x + 1} = 3

What is the answer to 27^{x+2}=9^{6x+10} ?
The answer to 27^{x+2}=9^{6x+10} is x=-14/9
Solve for x: 27^{x+2}=9^{6x+10}
The solution is x=-14/9