What is the answer to (64)^x+(16)^{10}-4=0 ?

The answer to (64)^x+(16)^{10}-4=0 is No Solution for x\in\mathbb{R}

Solve for x: (64)^x+(16)^{10}-4=0

The solution is No Solution for x\in\mathbb{R}

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(64)^{x} + (16)^{10} - 4 = 0

No Solution for x \in R

Solution steps

(64)^{x} + (16)^{10} - 4 = 0

Move

1 6^{10}

to the right side

6 4^{x} - 4 = - 1 6^{10}

Move

4

to the right side

6 4^{x} = - 1 6^{10} + 4

Apply exponent rules

6 4^{x} = - (4^{2})^{10} + 4

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

e^{x^{2}} = 2

- 3.73 = - 4 x e^{- \frac{x}{4}}

(4^{n} \cdot 4^{5})^{3} = 4^{27}

9^{x - 5} = 27

(- 0.1 b) e^{- b (- 6.7416)} = 0.86083

What is the answer to (64)^x+(16)^{10}-4=0 ?
The answer to (64)^x+(16)^{10}-4=0 is No Solution for x\in\mathbb{R}
Solve for x: (64)^x+(16)^{10}-4=0
The solution is No Solution for x\in\mathbb{R}