What is the answer to 6(5^{x-4})=42 ?

The answer to 6(5^{x-4})=42 is x=(ln(7))/(ln(5))+4

Solve for x: 6(5^{x-4})=42

The solution is x=(ln(7))/(ln(5))+4

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6 (5^{x - 4}) = 42

x = \frac{ln ( 7 )}{ln ( 5 )} + 4

Decimal Notation

x = 5.20906 \dots

Solution steps

6 (5^{x - 4}) = 42

Divide both sides by

6

5^{x - 4} = 7

Apply exponent rules

(x - 4) ln (5) = ln (7)

Solve

(x - 4) ln (5) = ln (7) : x = \frac{ln ( 7 )}{ln ( 5 )} + 4

x = \frac{ln ( 7 )}{ln ( 5 )} + 4

9^{x} = 2 7^{3 - x}

2 3^{n} = - (5^{n})

7^{x} - 7 = 35 + 7^{3 - x}

3^{5 x - 3} = 21

What is the answer to 6(5^{x-4})=42 ?
The answer to 6(5^{x-4})=42 is x=(ln(7))/(ln(5))+4
Solve for x: 6(5^{x-4})=42
The solution is x=(ln(7))/(ln(5))+4