What is the answer to 3^{2x+3}-55=28(3^x-2) ?

The answer to 3^{2x+3}-55=28(3^x-2) is x=0,x=-3

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3^{2x+3}-55=28(3^x-2)

3^{2 x + 3} - 55 = 28 (3^{x} - 2)

x = 0, x = - 3

Solution steps

3^{2 x + 3} - 55 = 28 (3^{x} - 2)

Apply exponent rules

(3^{x})^{2} \cdot 3^{3} - 55 = 28 (3^{x} - 2)

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{3} - 55 = 28 (u - 2)

Solve

u^{2} \cdot 3^{3} - 55 = 28 (u - 2) : u = 1, u = \frac{1}{27}

u = 1, u = \frac{1}{27}

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 1 : x = 0

Solve

3^{x} = \frac{1}{27} : x = - 3

x = 0, x = - 3

1 0^{x} = 12 \cdot 1 0^{- x} + 4

3 e^{7 x - 2} + 5 = 29

1 0^{x} = 2772

x, h = e^{x}

2^{4 x} = 9

What is the answer to 3^{2x+3}-55=28(3^x-2) ?
The answer to 3^{2x+3}-55=28(3^x-2) is x=0,x=-3
Solve for x: 3^{2x+3}-55=28(3^x-2)
The solution is x=0,x=-3