What is the answer to 3^{2(x-1)}=7^2 ?

The answer to 3^{2(x-1)}=7^2 is x=(ln(7))/(ln(3))+1

Solve for x: 3^{2(x-1)}=7^2

The solution is x=(ln(7))/(ln(3))+1

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3^{2 (x - 1)} = 7^{2}

x = \frac{ln ( 7 )}{ln ( 3 )} + 1

Decimal Notation

x = 2.77124 \dots

Solution steps

3^{2 (x - 1)} = 7^{2}

Apply exponent rules

2 (x - 1) ln (3) = 2 ln (7)

Solve

2 (x - 1) ln (3) = 2 ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} + 1

x = \frac{ln ( 7 )}{ln ( 3 )} + 1

4^{7 x - x^{2}} = 4^{12}

5 (2^{2 p + 1}) - 17 (2^{p}) + 3 = 0

e^{e^{x}} = 6

2 7^{\frac{x - 2}{3}} = 81

(\frac{1}{2})^{6 - x} = 2

What is the answer to 3^{2(x-1)}=7^2 ?
The answer to 3^{2(x-1)}=7^2 is x=(ln(7))/(ln(3))+1
Solve for x: 3^{2(x-1)}=7^2
The solution is x=(ln(7))/(ln(3))+1