What is the answer to 73=19^x ?

The answer to 73=19^x is x=(ln(73))/(ln(19))

The solution is x=(ln(73))/(ln(19))

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73=19^x

73 = 1 9^{x}

x = \frac{ln ( 73 )}{ln ( 19 )}

Decimal

x = 1.45713 \dots

Solution steps

73 = 1 9^{x}

Apply exponent rules

ln (73) = x ln (19)

Solve

ln (73) = x ln (19) : x = \frac{ln ( 73 )}{ln ( 19 )}

x = \frac{ln ( 73 )}{ln ( 19 )}

129 6^{x + 1} = 6^{x + 4}

2^{2 x} = 51

a, x (a + b) = x^{ab}

9^{x^{2} - x} = 81

3 e^{- 2 x} = 5