What is the answer to 3^{3x-2}=\sqrt[3]{9} ?

The answer to 3^{3x-2}=\sqrt[3]{9} is x= 8/9

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3^{3x-2}=\sqrt[3]{9}

x = \frac{8}{9}

Solution steps

Apply exponent rules

3 x - 2 = \frac{2}{3}

Solve

3 x - 2 = \frac{2}{3} : x = \frac{8}{9}

x = \frac{8}{9}

2^{x + 5} = 8^{x}

4 9^{p} = 1

y, z = x^{y}

3 \cdot 2 7^{x - 2} = 9^{x}

7^{5 x - 4} = 56

What is the answer to 3^{3x-2}=\sqrt[3]{9} ?
The answer to 3^{3x-2}=\sqrt[3]{9} is x= 8/9
Solve for x: 3^{3x-2}=\sqrt[3]{9}
The solution is x= 8/9