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Popular >

solvefor y,-2^y+5=7x

Solution

solve for

y, - 2^{y} + 5 = 7 x

Solution

y = \frac{ln ( - 7 x + 5 )}{ln ( 2 )}

Solution steps

- 2^{y} + 5 = 7 x

Move

5

to the right side

- 2^{y} = 7 x - 5

Divide both sides by

- 1

2^{y} = - 7 x + 5

Apply exponent rules

y ln (2) = ln (- 7 x + 5)

Solve

y ln (2) = ln (- 7 x + 5) : y = \frac{ln ( - 7 x + 5 )}{ln ( 2 )}

y = \frac{ln ( - 7 x + 5 )}{ln ( 2 )}

Popular Examples

5^{2 x + 3} = 125

57 = 2 5^{x}

(5^{x+1}-5^x)/4 =25

\frac{5 ^{x + 1} - 5 ^{x}}{4} = 25

(2^x)/(2^{3x)}=2^{2x}

\frac{2 ^{x}}{2 ^{3 x}} = 2^{2 x}

9^{x-4}=27^{5-2x}

9^{x - 4} = 2 7^{5 - 2 x}

Frequently Asked Questions (FAQ)

What is the answer to solvefor y,-2^y+5=7x ?
The answer to solvefor y,-2^y+5=7x is y=(ln(-7x+5))/(ln(2))