What is the answer to 5*25^{x+2}=125^{2x} ?

The answer to 5*25^{x+2}=125^{2x} is x= 5/4

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5*25^{x+2}=125^{2x}

5 \cdot 2 5^{x + 2} = 12 5^{2 x}

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

5 \cdot 2 5^{x + 2} = 12 5^{2 x}

Apply exponent rules

2 (x + 2) + 1 = 6 x

Solve

2 (x + 2) + 1 = 6 x : x = \frac{5}{4}

x = \frac{5}{4}

7^{5 x^{2} - 42 x} = 1 0^{125 - 42 x}

t, e^{k t} = \frac{1}{7}

3 ∣ 2^{x} - 1 ∣ = 2^{x}

4^{x} + 4^{x + 1} = 20

3 x e^{x} + x^{2} e^{x} = 0

What is the answer to 5*25^{x+2}=125^{2x} ?
The answer to 5*25^{x+2}=125^{2x} is x= 5/4
Solve for x: 5*25^{x+2}=125^{2x}
The solution is x= 5/4