What are the solutions to the equation 2(x^2-8)+7=-3 ?

The solutions to the equation 2(x^2-8)+7=-3 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 2(x^2-8)+7=-3

The zeros of 2(x^2-8)+7=-3 are x=sqrt(3),x=-sqrt(3)

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2 (x^{2} - 8) + 7 = - 3

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

2 (x^{2} - 8) + 7 = - 3

Move

7

to the right side

2 (x^{2} - 8) = - 10

Divide both sides by

2

x^{2} - 8 = - 5

Move

8

to the right side

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

9 m + 63

\frac{1}{3} + \frac{1}{3} - \frac{1}{6}

\frac{9}{10} - \frac{3}{14}

(4 - 3)^{\frac{2}{2}}

3 x^{2} + x + 6 = 0

What are the solutions to the equation 2(x^2-8)+7=-3 ?
The solutions to the equation 2(x^2-8)+7=-3 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 2(x^2-8)+7=-3
The zeros of 2(x^2-8)+7=-3 are x=sqrt(3),x=-sqrt(3)