What is the answer to 6^{x-3}=17 ?

The answer to 6^{x-3}=17 is x=(ln(17))/(ln(6))+3

Solve for x: 6^{x-3}=17

The solution is x=(ln(17))/(ln(6))+3

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6^{x - 3} = 17

x = \frac{ln ( 17 )}{ln ( 6 )} + 3

Decimal Notation

x = 4.58124 \dots

Solution steps

6^{x - 3} = 17

Apply exponent rules

(x - 3) ln (6) = ln (17)

Solve

(x - 3) ln (6) = ln (17) : x = \frac{ln ( 17 )}{ln ( 6 )} + 3

x = \frac{ln ( 17 )}{ln ( 6 )} + 3

(\frac{1}{2})^{x} = \frac{1}{8}

3^{x + 1} = 3^{x} + 18

3^{5 x + 2} = 9^{x + 4}

\frac{1}{81} = 3^{x}

e^{k} = 4.5

What is the answer to 6^{x-3}=17 ?
The answer to 6^{x-3}=17 is x=(ln(17))/(ln(6))+3
Solve for x: 6^{x-3}=17
The solution is x=(ln(17))/(ln(6))+3