What is the answer to (5^x)(5^{x-1})=10 ?

The answer to (5^x)(5^{x-1})=10 is x=(ln(50))/(2ln(5))

Solve for x: (5^x)(5^{x-1})=10

The solution is x=(ln(50))/(2ln(5))

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(5^{x}) (5^{x - 1}) = 10

x = \frac{ln ( 50 )}{2 ln ( 5 )}

Decimal Notation

x = 1.21533 \dots

Solution steps

(5^{x}) (5^{x - 1}) = 10

Apply exponent rules

(x + x - 1) ln (5) = ln (10)

Solve

(x + x - 1) ln (5) = ln (10) : x = \frac{ln ( 50 )}{2 ln ( 5 )}

x = \frac{ln ( 50 )}{2 ln ( 5 )}

7^{5 x - 12} = 343

e^{c} = 4

7^{x^{2} - x} = 1

x e^{x} - 1 = 0

100 = \frac{300}{1 + e ^{4 - x}}

What is the answer to (5^x)(5^{x-1})=10 ?
The answer to (5^x)(5^{x-1})=10 is x=(ln(50))/(2ln(5))
Solve for x: (5^x)(5^{x-1})=10
The solution is x=(ln(50))/(2ln(5))