What is the answer to 4^{5-9x}= 1/(8^{x-2)} ?

The answer to 4^{5-9x}= 1/(8^{x-2)} is x= 4/15

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4^{5-9x}= 1/(8^{x-2)}

4^{5 - 9 x} = \frac{1}{8 ^{x - 2}}

x = \frac{4}{15}

Solution steps

4^{5 - 9 x} = \frac{1}{8 ^{x - 2}}

Apply exponent rules

2 (5 - 9 x) = 3 (- x + 2)

Solve

2 (5 - 9 x) = 3 (- x + 2) : x = \frac{4}{15}

x = \frac{4}{15}

Verify Solutions:

x = \frac{4}{15}

True

The solution is

x = \frac{4}{15}

\frac{1}{2} = 4^{x}

225 e^{\frac{x}{4}} = 45

e^{x - 3} = 6

3^{2 x + 2} + 8 \cdot 3^{x} - 1 = 0

y, x = e^{y + 1}

What is the answer to 4^{5-9x}= 1/(8^{x-2)} ?
The answer to 4^{5-9x}= 1/(8^{x-2)} is x= 4/15
Solve for x: 4^{5-9x}= 1/(8^{x-2)}
The solution is x= 4/15