What is the answer to 1=log_{2}(ln(2^x)) ?

The answer to 1=log_{2}(ln(2^x)) is x= 2/(ln(2))

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1=log_{2}(ln(2^x))

1 = lo g_{2} (ln (2^{x}))

x = \frac{2}{ln ( 2 )}

Decimal Notation

x = 2.88539 \dots

Solution steps

1 = lo g_{2} (ln (2^{x}))

Rewrite the equation with

2^{x} = u

1 = lo g_{2} (ln (u))

Solve

1 = lo g_{2} (ln (u)) : u = e^{2}

u = e^{2}

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = e^{2} : x = \frac{2}{ln ( 2 )}

x = \frac{2}{ln ( 2 )}

6^{x - 1} = 36

2^{y} = 4

5^{2 x} - 2 \cdot 5^{x} = 24

x + 3^{x} = 4

What is the answer to 1=log_{2}(ln(2^x)) ?
The answer to 1=log_{2}(ln(2^x)) is x= 2/(ln(2))
Solve for x: 1=log_{2}(ln(2^x))
The solution is x= 2/(ln(2))